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And I do mean everyone. There are 11 declared Republican candidates and 5 declared Democrats. What little polling there’s been indicates that we should end up with a standard partisan election in June, with Karen Handel (former Secretary of State of Georgia and former candidate for Governor and Senator) for the Republicans, and Jon Ossoff, former congressional aide, current maker of investigative films, and person who is younger than me and therefore unelectable due to things he posted on Facebook, for the Democrats.

But this post is not about politics. It’s about yard signs. If I’m not mistaken – and I very well may be mistaken – I’m seeing more yard signs than I did for the presidential election. Now, I live in an American suburb, which means that there are houses on main roads that people pass by, and there are houses in subdivisions that nobody drives by unless they live in the subdivision. And I’m noticing that yard signs seem to be more prevalent on the main roads.

Is this true? It’s hard to count and drive at the same time – it’s easy enough to count the signs, but counting the houses is tricky, and without the denominator this would be worthless – and I wouldn’t have been able to get a large enough sample anyway. But it seems to make sense. I live on one of those roads that nobody drives down unless they live on it. If I had a sign, who would see it? I’m not much for putting up signs anyway, but if I were, I’d be more likely to if I lived on a road where the sign would have more effect. As it turns out, I’m not the only one. The paper Understanding Visible Political Participation: An Analysis of Yard Sign-Displays during the 2008 Presidential Election came up with a model to predict which properties display yard signs, and traffic volume (subjectively coded into six categories from “dead-end” to “major artery” does turn out to be significant. I found out about this from a *Slate* article by Sasha Issenberg which rounds up a lot of the research on signs.

By the way, this is one of those things that’s very hard to Google, because the advice on how to put up signs swamps the research on signs. But the conventional wisdom seems to agree that signs on busier roads are more valuable. One sign vendor writes (emphasis added):

- The most effective way is to combine your dooknocking [sic] with your yard sign recruitment. Target the
busiest streetsfor door to door work first, and for those people who are friendly, ask them if it would be okay to put a sign in the yard.

Perhaps this is why nobody bothers to canvass my neighborhood and offer me a sign.

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From the third term on, each term of the sequence of real numbers is the sum of the preceding two terms; that is, for . If , what is the sum of all the ten terms?

I’d heard this one before (though it’s hard to find a source for things like this – the cloesst I could find was this Math StackExchange question. The solution is as follows: we can write as linear combinations of . In particular we have , where the general term is (we’ll use this later). Here is the th Fibonacci number, where . Adding everything up we get

and doing those sums gives . But , and so the sum is just . For example, consider the sequence with :

which you can easily verify sums to 187. In the case where you actually have the whole sequence, this is a reasonably well-known “arithmetic trick” that one can show grade school children! The HCSSiM version, of course, doesn’t let you see the whole sequence.

But are there similar tricks to this with shorter or longer sequences? That’s usually the way with the Fibonacci numbers; facts about them tend to be parametrizable. A bit of experimentation shows us that with six terms we have

See for example the series ; its sum, 56, is four times its fifth term. And with fourteen terms we have

(I’ll leave you to come up with your own example.) It would appear that we have , where the are the Lucas numbers . Consider the sum of the first terms satisfying a Fibonacci recurrence:

Now we have and . These are both special cases of the identity givnen in Wikipedia, . So we have

.

So the sum of a fourteen-term Fibonacci sequence is equal to a multiple of the ninth term; the sum of a ten-term Fibonacci sequence, a multiple of the seventh term; the sum of a six-term Fibonacci sequence, a multiple of the fifth term. What of a sum of a two-term Fibonacci sequence? We get . Recall — the sum of the first two terms is, trivially, a multiple of the third term.

(I don’t claim this is original. Only that I had some fun thinking about it. That probably means I need to get a life.)

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mathematical research is a transnational activity, in that the specific nationality of individual members of a research team or research community are (or should be) of no appreciable significance for the purpose of advancing mathematics.

Not surprisingly, then, given the current political situation, 90 percent of people identifying themselves as “mathematician” donating money to US political campaigns give to Democrats, according to analysis by Verdant Labs. Only 85 percent of those calling themselves “Professor of Mathematics” do. One possible explanation is the those identifying as “professor of mathematics” identify more with their position as educators, and education doesn’t have the same “transnational” quality.

You can download the data from the FEC if you want! I suspect there’s something interesting in here… let’s see how my new laptop handles those twenty million records.

And please point me to interesting analysis of FEC data on campaign contributions that’s already been done! A couple things I’ve seen from the data science community:

- Someone named Gary did some analysis in November of 2015, for the 2016 presidential cycle as it had unfolded thus far in Ohio
- Verdant Labs has also looked at the politics of first names .

But there is surprisingly little out there, given that this is such an interesting data set!

If you want to do something more useful than navel-gazing at data, I recently came across Data for Democracy, and Moon Duchin is organizing a summer school on the geometry of redistricting, including some training in being an expert witness in gerrymandering cases. Will someone write the `gerrymandr` R package?

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I feel reasonably sure that I’ve seen somewhere a suggestion that the Doomsday clock could be calibrated such that the probability of Doomsday is proportional to the reciprocal of the time towards midnight. If I had to guess this is an idea of Douglas Hofstadter but I don’t have his books at hand right now. (This is annoyingly hard to Google, because the Doomsday argument gets in the way.)

Some people have objected to the thirty-second news as unnecessary fine-tuning. But in this reciprocal view that isn’t so strange; it corresponds to adjusting the probability of Doomsday from, say, one per thirty years to one per twenty-five years. There have been moves from five to six minutes before, to which this is proportional. Also, the clock was at 11:57; it’s only been at 11:58 once before, after the US and Soviet Union did thermonuclear tests in close temporal proximity in 1953. So unless they want to say it is literally *the worst it has ever been*, two and a half minutes to midnight it is.

Here’s the full statement of the *Bulletin*. They appear to be saving themselves some room:

The board’s decision to move the clock less than a full minute—something it has never before done— reflects a simple reality: As this statement is issued, Donald Trump has been the US president only a matter of days.

Let’s see what happens next year.

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Neal Koblitz, Why STEM Majors Need the Humanities in the *Chronicle of Higher Education*

Francis Su’s address as retiring president of the Mathematical Assocation of America, Mathematics for Human Flourishing.

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Sometime in the 21st century, the following conversation takes place:

“Don’t throw out that calendar! You could reuse it in the future, when the days and dates on the calendar match up again.”

“OK, but that won’t happen for a long time. Forty years, in fact.”

“You’re right! In fact, this calendar has never had a 40-year gap before.”

What year is it?

We can start by observing that there are 14 possible calendars. To know what calendar we can use in a given year, we have to know whether it’s a common (non-leap) or leap year, and the day of the week of one particular day. Let’s pay attention to what John Conway called “Doomsday”, i. e. the last day of February (February 28 in common years, and February 29 in leap years). Doomsday moves forward one day in the week each year, except two days in each leap year – so, for example, Doomsday (February 28) 2015 was a Saturday, Doomsday (February 29) 2016 was a Monday, and Doomsday (February 28) 2017 will be a Tuesday.

So let’s consider when a 40-year gap will happen. A 40-year gap can’t begin with a common year. Say the year Y is the year after a leap year; then Doomsday of Y+6 will be the same as Doomsday of Y, since over those six years Doomsday will move forward six days in the week, plus one day for the leap year. If Y is two or three years after a leap year, then Y + 11 and Y will have the same Doomsday – Doomsday moves forward 11 days, plus three for the leap years. (This is basically cribbed from the calendar FAQ.

The exception is if Y is very near the end of a century that isn’t divisible by 400 – near enough that one of the otherwise intervening leap years would be a common year. In any of these cases Y and Y + 12 share a calendar – there are two intervening leap years.

(In most cases Y and Y + 28 share a calendar – that is, if no end-of-century common year intervenes. But we’d still have to do the casework anyway.)

So we must be in a leap year. But a 40-year gap, from Y to Y + 40, should lead to a Doomsday being one day later (40 + 10 = 50, which is one more than a multiple of seven) We must be in a leap year for which there are only NINE leap years in the next 40 – i. e. we’re in one of 2064, 2068, …, 2096 – since 2100 isn’t a leap year. But the calendars 2064 and 2068 will be repeated in 2092 and 2096 (28 years later, with 7 leap years), and 2092 and 2096 will be repeated twelve years later (with two leap years). So we must be in one of the five years 2072, 2076, 2080, 2084, and 2088.

Which one is it? See the note “You’re right! In fact, this calendar has never had a 40-year gap before.” By the same reasoning as above, 40-year gaps in the past could have only happened in starting in one of the leap years 1672-1688, 1772-1788, 1872-1888, since the Gregorian calendar – which insituted our current leap-year policy and thus the nine-in-forty loophole started in 1582. (1600 and 2000 were leap years, so 15xx and 19xx candidates are out.)

Doomsday in 1672 in the Gregorian calendar was Monday. I cheated by looking it up. For example you can type `ncal -sFR 1672` at your friendly Unix prompt, where “FR” is the country code for France, a country that adopted the Gregorian calendar at the beginning. Honestly, it doesn’t matter what day of the week Doomsday in 1672 is, only the relationships between the Doomsdays. In 1772 Doomsday is Saturday (124 days later in the week, that is, 100 years plus 24 leap years); in 1872 it’s Thursday. So we can work out the doomsdays for each leap year. These are:

1672 through 1688: Mon, Sat, Thu, Tue, Sun

1772 through 1788: Sat, Thu, Tue, Sun, Fri

1872 through 1888: Thu, Tue, Sun, Fri, Wed

2072 through 2088: Mon, Sat, Thu, Tue, Sun

All seven days of the week occur here, so the puzzle seems to be broken. But if we’re in a country which switched calendars after 1672 but before 1772 – like, say, Great Britain and its colonies, which changed over in 1752 – then the doomsday-Monday calendar won’t have occurred yet but the other six have. (Again from the calendar FAQ), we could also be pretty much anywhere else in Protestant-dominated Europe or colonies thereof.) The answer is 2072.

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Other analyses include:

- Snopes, based on lists of notable deaths put out by various media organizations – but of course there’s probably some bias towards keeping the lists roughly the same length as in previous years.
- Researchers at the MIT media lab, C. Candia-Castro-Vallejos, Cristian Jara-Figueroa, César A. Hidalgo, who concluded that
*fewer*famous people died in 2016 than expected (although not many fewer) Their notion of fame attempts to be more cross-cultural and looks at the number of*languages*someone has a Wikipedia article in.

(Via Metafilter.).

It may just be that the Anglo-American axis had a bad year (and of course Brexit and the ascendancy of Donald Trump can’t have helped the mood in (the media in) either of those countries…

But 2017 has a total solar eclipse in the US, so we’ll be okay.

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